or
or
It is given that a+1a=3
Using identity,
(a+b)2=a2+2ab+b2,
we have
a2+1a2=(a+1a)2−2
⇒ a2+1a2=32−2
⇒ a2+1a2=9−2
⇒ a2+1a2=7
Squaring both sides we get,
(a2+1a2)2=72
⇒ (a2)2+(1a2)2+2(a2)(1a2)=72
⇒ a4+1a4+2=49
⇒ a4+1a4=47
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